Measuring Potential Difference Across 4.5kOhm Resistor w/ Voltmeter

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To measure the potential difference across a 4.5 kOhm resistor in a circuit with a 50.0-V battery and a 10.0 kOhm voltmeter, the voltmeter's internal resistance must be considered. The voltmeter should be treated as a parallel resistor to the 4.5 kOhm resistor, affecting the total resistance and the voltage drop. The initial calculations provided were incorrect, leading to confusion about the correct approach. The correct method involves using the voltage divider rule to determine the potential difference accurately. Understanding how to incorporate the voltmeter's resistance into the circuit is crucial for obtaining the true measurement.
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Homework Statement



A circuit consists of a series combination of 6.00 -kOhm and 4.50 kOhm resistors connected across a 50.0-V battery having negligible internal resistance. You want to measure the true potential difference (that is, the potential difference without the meter present) across the 4.50 -kOhm resistor using a voltmeter having an internal resistance of 10.0 kOhm.

What potential difference does the voltmeter measure across the 4.50 -kOhm resistor?

Homework Equations


The Attempt at a Solution


I tried doing (50*10000)/V - 10,000 = 4500 and solving for V but I got 35.5 and this isn't the right answer. There are no formulas in my book for calculations with voltmeters I got this formula online so I'm not even sure if it is correct can anyone help me out?
 
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Hi physstudent1,

physstudent1 said:

Homework Statement



A circuit consists of a series combination of 6.00 -kOhm and 4.50 kOhm resistors connected across a 50.0-V battery having negligible internal resistance. You want to measure the true potential difference (that is, the potential difference without the meter present) across the 4.50 -kOhm resistor using a voltmeter having an internal resistance of 10.0 kOhm.

What potential difference does the voltmeter measure across the 4.50 -kOhm resistor?

Homework Equations





The Attempt at a Solution


I tried doing (50*10000)/V - 10,000 = 4500 and solving for V but I got 35.5 and this isn't the right answer. There are no formulas in my book for calculations with voltmeters I got this formula online so I'm not even sure if it is correct can anyone help me out?

Treat the voltmeter as just a resistor being hooked in parallel to the 4.5 kOhm resistor. In this new circuit, what is the potential difference across the 4.5 kOhm resistor?
 

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