Measuring torque acting on motor shaft?

AI Thread Summary
To measure the average torque required to turn an auger with an electric motor, it's essential to understand the relationship between power input, output, and motor efficiency. The motor is identified as a DC type, and efficiency typically ranges from 60% to 75%. Direct torque measurement can be achieved by using a sensor between the motor and the auger or by assessing the torque applied to the motor's mount. Efficiency varies with the motor's operating point, so it is advisable to focus on measuring voltage and RPM first. Ultimately, aligning the torque absorbed by the auger with the motor's maximum efficiency torque is crucial for optimal performance.
robertjordan
Messages
71
Reaction score
0
I have an electric motor that I am using to turn an auger to dispense pet food. I want to measure the average torque required to turn this auger at a given rpm.

I know Powerin = Voltage into motor * Current into motor
and Powerout = Torque exerted by shaft * RPM of auger
and Powerout = Efficiency of motor * Powerin

But how can I find the efficiency of the motor at different voltage inputs? I don't know anything about this motor (I don't even know if it's an AC or DC motor) beyond that it works when connected to a battery and that it changes directions when I swap the leads. How can I find average torque exerted on the shaft by the pet food? I can measure RPM, VoltageIn, and CurrentIn...
 
Engineering news on Phys.org
It might be possible to measure the torque directly, for example by measuring the torque the motor applies to it's mount. The other possibility is to insert a sensor between motor and auger.

https://www.transducertechniques.com/sts-torque-sensor.aspx
 
I wouldn't worry about efficiency yet because it varies depending on the motor's operating point. The torque constant can be deduced from speed versus voltage curves. Speed and voltage are easy to measure. From what I've seen, measuring torque directly of a small DC motor requires comparatively elaborate and sensitive instrumentation.

Anyway, let's assume, for example, you want your motor to operate at maximum efficiency. In that case you then want the torque absorbed by the auger to equal the torque produced by the motor at the motor's maximum efficiency speed.

Technical correction: In the power out formula, torque is a physical quantity, whereas RPM is a unit of measure. I think you'd like all the variables to be physical quantities in this type of equation.
 
Hi all, i have some questions about the tesla turbine: is a tesla turbine more efficient than a steam engine or a stirling engine ? about the discs of the tesla turbine warping because of the high speed rotations; does running the engine on a lower speed solve that or will the discs warp anyway after time ? what is the difference in efficiency between the tesla turbine running at high speed and running it at a lower speed ( as fast as possible but low enough to not warp de discs) and: i...
Back
Top