(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

ParticleAand partidcleBare held together with a compressed spring between them. When they are released, the spring pushes them apart, and they then fly off in opposite directions, free of the spring. The mass ofAis 3 times the mass ofB, and the energy stored in the sring was 76 J. Assume that the spring has negligible mass and that all its stored energy is transferred to the particles. Once that transfer is complete, what are the kinetic energies of each particle?

2. Relevant equations

E=const.

For the system: total U_i + K_i=total U_f + K_f

3. The attempt at a solution

[tex]U_i + K_i = U_f + K_f[/tex]

K_i=0, U_f=0

[tex]U_i=K_f[/tex]

[tex]U_i=K_{Af}+K_{Bf}[/tex]

[tex]U_i=\frac{1}{2}m_Av_A^2+\frac{1}{2}m_Bv_B^2[/tex]

Let m_B=m, so m_A=3m

[tex]76 J=\frac{1}{2}3m+\frac{1}{2}mv_B^2[/tex]

At this point, I noticed that if the velocities are the same, K_A will be 3 times as large as K_B. Sure enough, the answer is that the U_i has been divided into 4 parts--but paticlehas 57 J and paticleBhas 19 J!A

How was I supposed to get there?

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# Mechanical Energy Transfer

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