Mechanical principles - Stess and modulus of elasticity

AI Thread Summary
The discussion focuses on calculating the towing capacity and extension of a steel bar under load. The user calculates the stress and confirms that the proposed load limit is acceptable, as the safety factor exceeds the required value. They also attempt to determine the change in length under maximum load but struggle with unit conversions and understanding the relationship between MN and GN. Clarifications are provided regarding the units of stress and the factor difference between MN and GN. The user expresses gratitude for the guidance and plans to practice further to solidify their understanding.
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Mechanical principles - Stress and modulus of elasticity

Homework Statement


A 2.2m long steel towing bar of solid circular section diameter of 45mm is expected to carry a maximum load of 210 kN. The safety factor is 4; and for the steel the UTS is 540 MNm-2 and the modulus of elasticity is 200 GNm-2

i) Calculate the actual towing capacity of the bar and state whether the proposed limit is acceptable
ii) Determine the extension of the bar under the maximum proposed load

Homework Equations



i) σ = Load / Area
Proposed limit acceptable= SF = UTS / σ

ii) Change in length = (σ / Modulus of elasticity) / Length

The Attempt at a Solution



Hi I have worked out what I think is right but I have trouble writing the correct units, I will put what i have worked out could someone check if I am right please, thank you very much:-

i) σ = Load / Area = 210kN / ((∏(45 x 10-3) / 4)

=

840x10-3 / 6.362x10-3 = 132.04 (now I think this is MNm2)

Proposed limit acceptable = SF = 540 / 132.04 = 4.09

So the proposed limit in this case is acceptable as it is over the required Safety Factor of 4

ii) Change in length = (132.04 / 200) x 2.2

= 0.66 x 2.2 = 1.45mm (??)
 
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If the load is in Newtons and the area is in m^2, what are the units of load/area?
Hint: it's not MNm^2.

If P/A is in MNm^-2 and E is in GNm^-2, then what are the units of (P/A)/E?
Do MN and GN cancel without using any other factors?
 
Hi steamking this is where i draw a mental block, i don't know why but I am working on it
1st point putting it like that is it Nm^2?

2nd point do you mean that both ^-2 cancel each other out leaving MNm and GNm?

Thanks, I keep telling myself i will get this!
 
My point is, if you divide a force by an area, a la P/A, the units must be N/m^2 or alternately, Nm^-2 (You do know there is a difference between a positive and a negative exponent, don't you?)

On the second point, what is the difference between 1 MN and 1 GN? How many MN are in 1 GN? In other words, your calculation of the change in length omits a factor of 1000, although the final answer is correct.
 
Thankyou very much for taking the time in showing me where i am going wrong SteamKing, that definitely makes more sense, I am going to go and do some more examples to make sure its sinked in whilst its still fresh! Thanks again
 
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