Mechanics, conservation of momentum.

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SUMMARY

The discussion revolves around the mechanics of a tank (mass M) containing water (mass m) on a frictionless surface, specifically analyzing the conservation of momentum when water flows out of the tank. Participants concluded that as water exits the tank, the tank moves in the opposite direction due to the conservation of momentum, leading to the expression v1f = -(m2/m1) (v2f) for final velocity. The conversation also highlighted the need to consider the effects of pressure and gravity on the system, particularly when determining the distance traveled and final velocity of the tank.

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  • Knowledge of gravitational effects on moving bodies
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  • #31
I have thought about this problem a bit and it seems to me that the tank should move to -x direction with a constant velocity(conservation of momentum) until the water hits the vertical part of the tap after which the tank would stop moving.
 
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  • #32
sg001 said:
But one thing that confuses me is how can this be the speed of the tank if we found out the tank does not move??

Exactly. The tank does not move, so this tells you that the speed of the tank is zero.
 
  • #33
i checked with my physics instructor and the answer is not zero the tank does have a final velocity!
now I am really confused.
help!
 

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