Mechanics homework confusion

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The discussion centers on confusion regarding a mechanics homework problem involving right triangles and strings connected to a block. The main issue is whether to create two right triangles based on the provided diagram or to assume the strings touch each other within the block, affecting the calculations. One participant suggests considering a triangle with sides 1.25 m, 2 m, and 1.25 m, assuming the strings meet at the block's center of mass. There are also suggestions to either state that the question cannot be answered as posed or to revise it for clarity. The conversation highlights the importance of clear problem statements in mechanics to avoid confusion.
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Homework Statement
Mechanics homework
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I have been given the following homework:
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For the first question a), I am not sure if i should create 2 right triangles for the strings as drawn in the picture, where the sum of the sides opposing the block are not equal to 2, or if i should say the strings go into the block and touch each other, so that the right triangles created have sides opposing the block equal to 2. If i choose the first option, which makes the most sense, the length 2 m becomes useless, and im not sure how i would solve it. Does anyone have any ideas?
Thank you in advance.
 

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I believe that you can consider a triangle of sides 1.25-2-1.25, assuming that the two strings coincide with the center of mass of the block, and that the opposite ends coincide with the axis of rotation (since there is no given information that contradicts those assumptions).

Diagrams are usually drawn by other than the problem creator, reason for which can be confusing.

562F4D72-6322-4024-9F29-D720480B7D9A.webp
 
TomPag said:
For the first question a), I am not sure if i should create 2 right triangles for the strings as drawn in the picture, where the sum of the sides opposing the block are not equal to 2, or if i should say the strings go into the block and touch each other, so that the right triangles created have sides opposing the block equal to 2. If i choose the first option, which makes the most sense, the length 2 m becomes useless, and im not sure how i would solve it. Does anyone have any ideas?
You could:

a) State that you believe the question posed can’t be answered and briefly explain why.

b) Propose a revision to make answers possible. E.g. replace the 4 kg ‘rectangular’ mass with a 4 kg point mass*.

c) Provide answers based on b).

It may be worth noting that a right-angled triangle with hypotenuse 1.25 m and another side 1.00 m is, in fact, a ‘3-4-5’ triangle.

*Edit: I originally typed '5 kg' but I meant '4 kg'.
 
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