Mechanics, specifically Moment question

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SUMMARY

The discussion centers on calculating moments in mechanics, specifically using the equations M = Fx(Perpendicular distance) + Fy(Perpendicular distance) and M = Fd for couples. Participants clarify that the moment at point D is influenced by the line of action of the force, emphasizing that the resultant force remains constant regardless of its location. The concept of the line of action is defined as the direction along which the force acts, which is crucial for understanding how moments are generated in different locations.

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Homework Statement


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Also, I am not entirely sure what the question is exactly asking. Also, what does the line of action represent?

Homework Equations



M = Fx(Perpendicular distance) + Fy(Perpendicular distance)

For couples:

M=Fd

The Attempt at a Solution



i was thinking that i need to find the moment at D, but wouldn't the resultant force still be the same? except located at D? However, since this is a couple, would the moment be the same everywhere?
 
Last edited:
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A force located at D doesn't give a moment (in D).
You shoud find a force located somewhere else than D.

A hint: the text speaks about LINE of action. Why ?
 
Wouldnt the force anywhere still be 48 N since the couple cancels each other out, and leaves only the moment?

Also, is the line of action just the direction/line that the force follows?
 

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