- #36
M P
- 88
- 1
Back on track after break with V40 = -60.1+5.31j and V30 = -45.9+19.51j in a need of your physics assistance
Your value for V30 doesn't look right, and it's the important value here since it determines the current through Z4.M P said:Back on track after break with V40 = -60.1+5.31j and V30 = -45.9+19.51j in a need of your physics assistance
Yes! Showing your work is highly encouraged. Trying to determine where things are going awry from the results alone requires a good deal more effort :) Show your calculations, preferably with notations as to what the steps are trying to accomplish.M P said:Is it ok to show calcs? I did check it and I am not sure what is causing damage.
gneill said:Yes! Showing your work is highly encouraged. Trying to determine where things are going awry from the results alone requires a good deal more effort :) Show your calculations, preferably with notations as to what the steps are trying to accomplish.
You should be in a position to determine the node potentials from the results of your previous mesh calculations. V30, for example, is given by the potential across Z4. The mesh currents will yield that from Ohm's Law. Since your mesh calculations were successful, you have a "standard result" against which you can compare new results.M P said:I have another one to check V40 = 60.1j - 214.5 V30 = 74.3j - 200.3 ?
If by "first results" you mean the mesh analysis portion of the problem, then that's not required since I believe that you found the correct results there. If you are having difficulty achieving the same results with nodal analysis, then those are the calculations that need to be examined.M P said:Now what calcs you prefer from first results or second ?
I was trying to do complex numbers on this ...M P said:one more question is version of V1-V30/Z1-V30/Z4+V2-V40/Z3-V40/Z5=0 also work?
and on this ? that is what I understood to obtain V3 and V4 of this with complex numbers..M P said:one more question is version of V1-V30/Z1-V30/Z4+V2-V40/Z3-V40/Z5=0 also work?
before I go further -55.74 - 20.06j + 0.25 V40 - 0.05 j V40 ?gneill said:
I'm not seeing where that's coming from. Sorry.M P said:before I go further -55.74 - 20.06j + 0.25 V40 - 0.05 j V40 ?
That'll work. Or,Ebies said:I3(-Z3) - V2 - Z5(I3-I2) = 0...Eq 3 new and revised eq 3
While you can use either direction to achieve valid equations, you must be consistent in your choice. Once you've made a selection of current direction for a mesh you must not change it, otherwise where loops "touch" the current sums through the shared components will be compromised.Ebies said:when using mesh analysis to determine the voltage drop direction, do you use conventional current flow or do you use the clockwise current you chosen at the beginning when assigned your clockwise mesh currents...? I am asking so I know when to add or subtract when doing the "KVL" walk... I am a bit confused about what the sign needs to be when walking the "KVL" loop and you encounter components... spent a lot of time going through my books and watching online tutorials and its confused me even more now
Mesh Analysis is a method used to analyze complex electrical circuits by dividing them into smaller loops or meshes. It involves applying Kirchhoff's Voltage Law (KVL) to each mesh to determine the currents flowing through each component. Nodal Analysis, on the other hand, involves applying Kirchhoff's Current Law (KCL) to each node or junction in the circuit to determine the voltages at each node. While Mesh Analysis is better suited for circuits with many current sources, Nodal Analysis is more efficient for circuits with many voltage sources.
Kirchhoff's Voltage Law states that the algebraic sum of voltages around a closed loop in a circuit is equal to zero. In Mesh Analysis, KVL is used to write equations for each mesh in the circuit by considering the voltage drops across each component. These equations are then solved simultaneously to find the currents flowing through each component.
Dependent sources, such as voltage-controlled voltage sources or current-controlled current sources, can be handled in Mesh Analysis by treating them as independent sources. This means that the dependent source is included in the equations for each mesh and its value is determined by solving the equations simultaneously.
Yes, Mesh Analysis can be used for circuits with multiple loops by dividing the circuit into smaller meshes. Each mesh is then analyzed separately using KVL, and the results are combined to find the overall solution for the circuit.
Mesh Analysis is not suitable for circuits with many nodes or junctions, as it can become complex and time-consuming. It also cannot be used for circuits with non-linear elements, such as diodes or transistors. In addition, Mesh Analysis assumes that the current flows in one direction around each mesh, which may not always be the case in real circuits.