Mesh Current Analysis for a Series-Parallel Circuit

AI Thread Summary
The discussion focuses on mesh current analysis for a series-parallel circuit, emphasizing the correct application of Kirchhoff's Voltage Law (KVL) and the importance of sign conventions in setting up equations. The original poster struggles with incorrect current values for I1, I2, and I3, which deviate from instructor-provided answers. Key advice includes ensuring the correct direction of current flow across resistors and accurately calculating voltage drops based on these directions. The poster's initial equations for mesh analysis are identified as incorrect, particularly regarding the voltage drops across specific resistors. Properly applying these principles is essential for achieving accurate results in mesh current analysis.
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Homework Statement


problem3.jpg



Homework Equations


Not necessarily any equations ,just systematic approaches for mesh current analysis like using KVL
Also used cramer's rule


The Attempt at a Solution


My work:
http://i28.photobucket.com/albums/c216/aldodesigns/page1.jpg
http://s28.photobucket.com/albums/c216/aldodesigns/?action=view&current=page2.jpg

I found I1, I2, and I3 (I think) but they're not right. The answers my instructor gave us were 8A for the 110V source and 10A for the 12V source and I am way off. Did I set up my equations wrong?
 
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Take care of your signs. Across a resistor, the current direction is always from the more positive terminal to the more negative one. If you decided the direction of current than you have the voltage drop always in that direction. You do not have the freedom to choose which terminal of a resistor is more positive than the other one, and you do not know it before you solve the problem for the currents.

So your first equations for mesh 1 and 3 are wrong.

In case of mesh 1 you have the current I1 - I2 flowing through the 12 ohm resistor. Going clockwise, the voltage drop is 12(I1-I2). In mesh 3, I3 current flows through the 4 ohm resistor, causing 4 (I3) voltage drop.

ehild
 
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