Metallic cube with circular hole

  • Context: Graduate 
  • Thread starter Thread starter ShayanJ
  • Start date Start date
  • Tags Tags
    Circular Cube Hole
Click For Summary

Discussion Overview

The discussion revolves around a metallic cube with a circular hole at its center, focusing on determining the electric potential inside the cube when two sides are maintained at different potentials. Participants explore the implications of the cube's geometry and the presence of the hole on boundary conditions and potential calculations.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant describes a cube with side length d and thickness t, with a circular hole of radius a, and seeks help with boundary conditions for the potential function.
  • Another participant questions the clarity of the description, asking if the cube is solid or hollow, and requests more details about the configuration and applied potentials.
  • There is a suggestion that if the thickness t equals d, the object may not be a cube, and a proposal to consider using superposition with a cylinder.
  • A participant clarifies that the object is a conductor and inquires about solving the problem without the hole.
  • Another participant agrees that solving the problem without the hole seems straightforward and proposes a potential function of the form φ = Ax + B, indicating that constants can be determined from the given potentials.

Areas of Agreement / Disagreement

Participants express differing interpretations of the cube's geometry and configuration, leading to some confusion. There is no consensus on the exact nature of the problem or the boundary conditions required for solving it.

Contextual Notes

Participants highlight potential ambiguities regarding the definitions of the cube's dimensions and the implications of the hole on the electric potential. The discussion reflects uncertainty about the geometry and its impact on the solution.

Who May Find This Useful

Individuals interested in electrostatics, boundary value problems, and the behavior of conductors in electric fields may find this discussion relevant.

ShayanJ
Science Advisor
Insights Author
Messages
2,802
Reaction score
605
There is a cube with its sides equal to d and its thikness equal to t. It also has a circular hole at its center with radius a (a<<d). Two sides of the cube are maintained at potentials [itex]V_0[/itex] and [itex]-V_0[/itex].
I want to find the potential inside the cube but I see no way for obtaining the boundary conditions: the potential function at the boundary of the hole and the potential of the sides of the cube which are not connected to the battery. I just have no idea.Can anyone help?
Thanks
 
Physics news on Phys.org
This doesn't make any sense to me. Is it a solid cube? If so, the statement that the side = d defines the cube - what then does it mean to say the thickness = t? Is it a hollow cube with side = d and the thickness of the faces = t? If so, how can it have a hole at the center? Do you mean that one or more of the faces has a hole at the center? Also, which two sides have the applied potential? Two opposite sides? Two adjacent sides? Please describe it in more detail or provide a drawing.
 
Sorry...
 

Attachments

  • Cube with hole.jpg
    Cube with hole.jpg
    18 KB · Views: 457
That helps. So it is not a cube, unless d = t. Is it a dielectric? Can you use superposition, considering a solid "cube" superposed with a cylinder?
 
phyzguy said:
That helps. So it is not a cube, unless d = t. Is it a dielectric? Can you use superposition, considering a solid "cube" superposed with a cylinder?

Its a metal, a conductor!
I don't understand. Please clarify a bit!
 
OK, so it's a conductor with a current flowing through it. Do you know how to solve the problem without the hole?
 
phyzguy said:
OK, so it's a conductor with a current flowing through it. Do you know how to solve the problem without the hole?

Yeah, that seems easy.
The potential inside the cuboid is [itex]\phi=Ax+B[/itex] if we take the x-axis to be parallel to its lower edge. The constants A and B can be calculated easily using given potentials for two sides.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
7K
  • · Replies 3 ·
Replies
3
Views
975
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
5K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K