Micro electronic circuit problems

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A 10,000 Micro Farad capacitor with a tolerance of +20%/-50% has a possible range of values from 5,000 to 12,000 Micro Farads. For the 15-bit A/D converter with a full scale of 10 V, the least significant bit (LSB) value is calculated by dividing the full scale voltage by the number of steps, which is 32,768. The binary output code for an input voltage of 6.83 V can be determined using the formula: n-bit number = input voltage / full-scale voltage VFS. The discussion highlights the need for clarity on tolerance specifications and ADC calculations, suggesting that these may be homework questions better suited for a dedicated forum. Overall, the conversation emphasizes understanding basic electronic concepts and calculations.
Naeem
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Q1. A 10,000 Micro Farad capacitor has an asymmetric tolerance specification of +20%/-50% What is the possible range of values for this capacitor?

How do I do this problem ?

Q2. A 15-bit A/D converter has V(full scale) = 10 V. what is the value of the LSB> If the input voltage is 6.83 V, what is the binary output code of the converter?

What formula do I use here for the different parts ?

n- bit number = input voltage / ful-scale voltage VFS.

That's all I know !
 
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These sound like homework questions. If so, they should have been posted in one of the homework forums.

-1- Do you know what +20% means? If I have 10 of something, and I add 20%, how many total do I have now? What if I subtract 20% instead?

-2- A 4-bit ADC would have 16 steps, right? How many steps does a 15 bit ADC have? If those steps span voltage input readings from 0V to 10V, what is the voltage difference per step?
 
a1.
range [ 5000; 12000]

a2.
berkeman's explanation should suffice...
 
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