Minimum argument of a complex number

Amaru58
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Homework Statement



Find the minimum value of arg(z) where z satisfies the inequality |z + 3 -2i| </_ 2

Homework Equations



Is this working correct? Thank you for help in advance

The Attempt at a Solution



Z lies on a circle with radius 2 and centre -3,2

arg(z)min = pi - 2 tan^-1(2/3)?
= 113 degrees
= 1.97 radians?
 
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First note that any argument given by a point inside the circle is also given by a point on the circle so we need only look on the circle for solutions. Then the argument will be smallest when the tangent line to the circle passes through the origin since that will make the angle between the imaginary axis and the point on the circle as small as possible.
 
So if we draw two lines: 1) Joining the centre of the circle to the origin and 2) extending a tangent of the circle to the origin as this is where the minimum argument occurs?
Consequently two congruent triangles are formed (if we draw a line down form the centre of the circle perpendicular to the imaginary axis).
We can then find the minimum argument of this complex number as: pi - tan2/3
Therefore the minimum argument is 113 degrees which is 1.97 radians
I'm still not sure what is wrong with my working
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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