What Happens When You Mix a pH 8 Base with a pH 14 Base?

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Mixing a base with a pH of 8 and another with a pH of 14 will result in a final pH that falls between 8 and 14, influenced by the concentrations of each base and their respective pK values. The final pH is determined by the Henderson-Hasselbalch equation, and the volume of each base is crucial in this calculation. Since pH is logarithmic, the mixing process is non-linear, meaning that even small changes in concentration can significantly affect the final pH. A base with a pH of 8 is considered weak, especially when compared to a stronger base with a pH of 14, but it is important to note that a pH of 8 does not necessarily indicate a strong base that is simply diluted.
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Say i were to mix a basewith a pH of say 8, with a pH 14. what would my final pH be? 11?
 
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Serene_Chaos said:
Say i were to mix a basewith a pH of say 8, with a pH 14. what would my final pH be? 11?

it depends upon the concentrations of each, and the pK of the bases - but it is safe to say that your pH will be somewhere between 8-14.

the exact pH will follow the Henderson-Hasselbach eq.
 
...and of course, the volume of each base matters.
 
It would *have* to follow a non-linear mixing formula, since the pH number is logarythmic. pH9 is 10x more alkaline than pH8; pH10 is 10x more alkaline than pH9.
 
a base with a pH of 8 is very weak, do you think that the weak base will hydrolyze more or less when there already exists a significant concentration of hydroxide (consider this problem in terms of rates). I'll explain the specifics later.
 
GCT said:
a base with a pH of 8 is very weak

Not necessarilly. It can be strong, but diluted.
 
Say i were to mix a basewith a pH of say 8, with a pH 14. what would my final pH be? 11?

in the relative sense, as mentioned in the original post, yes it would be very weak...compared to one which would register a pH of 14.
 
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