Modern Algebra Problem: Equivalence Relations and Classes

OhyesOhno
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Homework Statement


There's this one exam problem that I cannot solve... Here it goes:

Consider the set Z x Z+. Let R be the relation defined by the following:

for (a,b) and (c,d) in ZxZ+, (a,b) R (c,d) if and only if ad = bc, where ab is the product of the two numbers a and b.

a) Prove that R is an equivalence relation Z x Z+
b) Show how R partitions Z x Z+ and describe the equivalence classes

Homework Equations



For equivalence relations we have to proof that it is reflexive (xRx), symmetric (aRb = bRa) and transitive (aRb bRc hence aRc)

The Attempt at a Solution



I already did part a... I just have trouble on b... how am I supposed to know the equivalence classes of this?
 
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Good! a was the hard part.

Start from the definition of "equivalence class": two elements are in the same class if and only if they are equivalent to each other.

Think about (a, 1). What pairs are equivalent to (a, 1)? that is, what (x,y) satisfy x*1= a*y? (Think about fractions: x/y.)
 
Any fraction would satisfy (a,1) right? Because if x/y = a/1, then a = x/y so any fraction will do it?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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