In the pole and barn paradox, if the observer (person A) closes the both doors simultaneusly (with respect to himself), when he sees the runner's stick (person B) is just inside and keeps it closed forever after that, how will things happen, will the runner be traped or the door will hit the stick? For those who don't know it here is the paradox. Person A is on the ground and person B is running with a long horizontal stick at relativistic speed. Then the length of the stick will appear to contract for A. So, he develops a cage equal in length of the observed length of the stick. He then asks the runner to run into the cage, and at the instant the runner appears to be completely in he closes both the door, for an instant. So, for that instant the stick should have to be contracted for Person B as well as it is fitting in a cage smaller than its proper length for B. (it is explained by saying that the closing of the door doesn't occurs simultaneusly so, even if A sees the stick completely inside for a instant its not the case with B). But what for my above modification?