Modified Coulomb model for hydrogen, minimising error

AI Thread Summary
The discussion focuses on determining the largest value of b in the modified Coulomb model for hydrogen, ensuring the ground-state energy aligns with the Coulomb model predictions to within one part in a thousand. The ground energy approximation is given as E_{1}^{(1)} ≈ -4b²/a₀² E_R, where E_R is 13.6 eV and a₀ is the Bohr radius. Participants clarify that the one part in a thousand refers to the acceptable difference between the two energy values as a fraction of the expected value, specifically Δ/13.6 ≤ 0.001. The challenge lies in calculating the maximum b while adhering to this precision constraint. The discussion emphasizes the need to equate the approximate and Coulomb model energies within the specified tolerance.
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Homework Statement


The ground energy can be approximated as

E_{1}^{(1)}\approx-\frac{4b^2}{a_0^2}E_R

Find the largest value of b that would be consistent with the ground-state energy of a hydrogen atom that agrees with the predictions of the Coulomb model to one part in a thousand

Homework Equations


E_R=13.6eV
a_0 is the Bohr radius

The Attempt at a Solution


I can transpose to make b the subject but not sure about the one part in a thousand.
 
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It refers to the difference between the two values as a fraction of the value. The values being the ground state energy of the hydrogen atom as per the two formulas. The difference should then be no more than 1000th or 0.001 of the expected value.

For example for a value of 10.0 cm +/- 0.5 cm the uncertainty 1 in 20 of the value.
 
Hi
So 13.6 \pm0.0136 \dfrac{0.0136}{13.6} would be one part in a thousand.

But how do I use that to find the maximum value of b so that E_1 agrees with E_R to one part in a thousand?
 
You have to find a value for b so that the ground-state energy of the atom according to the approximate formula, and the value from the Coulomb model do not differ by more than 1/1000. That is the difference between the two values, Δ, has to be such that

Δ/13.6 ≤ 0.001
 
Of course, thanks.
 
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