Molarity given percent solution and density.

AI Thread Summary
To calculate the molarity, molality, and mole fraction of a 12.0% lactose solution with a density of 1.06 g/mL, one must first determine the mass of lactose in a given volume of solution. The initial attempt at calculating molarity was incorrect due to unit conversion errors. The correct approach involves converting the percentage concentration to moles using the molecular weight of lactose and the solution's density. It's essential to track units throughout the calculations to ensure accuracy. Properly following these steps will yield the desired concentrations.
webz
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Homework Statement


Lactose (C12H22O11; MM=342) is a sugar found in mamalian milk. The density of a 12.0% solution is approximately 1.06 g/mL. What is the molarity, molality, and mole fraction of the solution?


Homework Equations


M=g/L, m=mol/kg, molefraction=mol/mol??


The Attempt at a Solution


I think I can get this one if I can just determine the molarity. I definitely did something wrong.

M=mol/L
1.06 / 1000 = .00106; .00106/342 = 3.099x10^-6M
I figured since I know g/mL as well as mol/g, I can divide to get mol/mL, then convert to get L. Apparently this is not the case?
 
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You're on the right track, just a few things you need to pay attention to:

1.06 grams of solution contains how many grams of lactose?

Also, show your units at all steps of the calculation to make sure you're converting correctly.
 
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Hmm, then let me try this again. I just want to find the moles of Lactose for now, then I think I got the rest.

1.06 g/mL * 1mol/342g * 12% lactose = 3.719x10^-4

Does that look right?

Thanks for the help btw.
 
That looks good, but remember to keep track of the units.
 
webz said:
I just want to find the moles of Lactose for now

Moles of lactose in what?

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