Moment of Inertia/ Kinetic Energy

AI Thread Summary
A flywheel, described as a solid disk rotating about its center, can store energy as rotational kinetic energy, making it a potential alternative to batteries in electric vehicles. The energy produced by gasoline during a 260-mile trip is approximately 1.3 x 10^9 J. The moment of inertia for a 20-kg flywheel with a radius of 0.34 m is calculated to be 1.156 kg·m². The angular velocity required to store this energy was initially miscalculated, but it was clarified that the distance of the trip is irrelevant to the energy calculation. The discussion emphasizes the importance of understanding units when converting angular velocity to revolutions per minute.
wallace13
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A flywheel is a solid disk that rotates about an axis that is perpendicular to the disk at its center. Rotating flywheels provide a means for storing energy in the form of rotational kinetic energy and are being considered as a possible alternative to batteries in electric cars. The gasoline burned in a 260-mile trip in a typical midsize car produces about 1.3 x 10 9 J of energy. How fast would a 20-kg flywheel with a radius of 0.34 m have to rotate in order to store this much energy? Give your answer in rev/min.



I= 1/2mr squared
J= 1/2 IW squared



.5*20*(.34*.34)
I=1.156
1.3 X 10 9 = .5 x 1.156 x W squared
W=47425.04558



My speed is obviously incorrect. I do not understand where the distance (260 mile trip) comes into play in this problem

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wallace13 said:
.5*20*(.34*.34)
I=1.156
1.3 X 10 9 = .5 x 1.156 x W squared
W=47425.04558
OK. What are the units of ω? You'll need to convert from those standard units to the requested units of rev/min.
I do not understand where the distance (260 mile trip) comes into play in this problem
It doesn't. It's just there to provide some background information so the problem seems realistic.
 
okay i got it. thanks
 
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