Moment of Inertia (not through symmetry axis)

AI Thread Summary
The moment of inertia for a solid cylinder rotating about an axis parallel to its symmetry axis but through its edge can be calculated using the parallel axis theorem. The standard moment of inertia formula for a solid cylinder is I = 0.5mr², but this needs to be adjusted for the new axis. By applying the parallel axis theorem, the equation becomes I = Icenter + mr², where Icenter is the moment of inertia about the center axis. For the given cylinder with a mass of 8.41 kg and a radius of 7.5 cm, this adjustment is essential for accurate calculations. Understanding these principles is crucial for solving related physics problems effectively.
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Homework Statement


What is the moment of inertia of a solid cylinder (of mass 8.41kg and radius 7.5cm) rotating about an axis parallel to the symmetry axis but passing through the edge of the cylinder?

Homework Equations


I=.5mr2,
but how does this change when the axis is passing through the edge of the cylinder?

The Attempt at a Solution


I can't attempt it intelligently until I have the correct equation. Once I do, I can finish it off myself.
 
Last edited:
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You will need the parallel axis theorem:

I=Icenter+mr2
 
Thanks so much!
 

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