What is the Moment of Inertia of a Book Pivoting at One Corner?

AI Thread Summary
To find the moment of inertia of a book pivoting at one corner, it can be approached using the parallel axis theorem, which allows for calculations based on standard formulas for rectangular slabs. The book's dimensions are 24 by 27 cm, and its behavior as a physical pendulum depends on its orientation during the swing. If the book is considered a point mass at its center of mass, the problem simplifies to that of a simple pendulum. Integrating to find the moment of inertia is possible, but using established tables and formulas is more efficient. Understanding the book's orientation is crucial for determining the nature of its motion.
armolinasf
Messages
195
Reaction score
0

Homework Statement



Suppose I have a book with dimensions 24 by 27 cm and its being pivoted at one of its corners so that it can swing along a plane parallel to itself. I'm supposed to find the period. But in order to do that I need to know its moment of inertia, would I have to write an integral using the definition of moment of inertia or is there some formula that I'm missing? Thanks
 
Physics news on Phys.org
armolinasf said:

Homework Statement



Suppose I have a book with dimensions 24 by 27 cm and its being pivoted at one of its corners so that it can swing along a plane parallel to itself. I'm supposed to find the period. But in order to do that I need to know its moment of inertia, would I have to write an integral using the definition of moment of inertia or is there some formula that I'm missing? Thanks

If you consider the book to be a point mass, at the centre of mass of the book, the problem will reduce to a simple pendulum.
 
The...period? Do you mean that the book is hanging vertically and acting as a physical pendulum? Because if it's horizontal, it's not even clear to me that you'd have a periodic motion.

You could integrate to find the moment of inertia, but moment of inertia tables will certainly have equations for the moment of inertia of a thing rectangular slab, and you could use the parallel axis theorem to get this for rotation around one of its corners ("thin" here meaning that you can ignore the third dimension -- the thickness).

See for example, here: http://en.wikipedia.org/wiki/List_of_moments_of_inertia
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Back
Top