Moment vector expression to magnitude of moment

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SUMMARY

The discussion focuses on calculating the magnitude and angle of the moment vector defined as moment = -2.8i - 1.53j + 2.24k. The magnitude of a vector is determined by squaring each component, summing them, and taking the square root. The participants emphasize the importance of understanding vector components and the correct application of mathematical operations to derive the magnitude. The tension force of 2.4 kN is also mentioned, indicating its relevance to the problem context.

PREREQUISITES
  • Understanding of vector components in three-dimensional space
  • Knowledge of vector magnitude calculation
  • Familiarity with trigonometric functions, specifically sine and cosine
  • Basic proficiency in using cross products in vector analysis
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  • Learn how to calculate the magnitude of a vector using the formula √(x² + y² + z²)
  • Study the application of cross products in physics and engineering contexts
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Students in physics or engineering courses, particularly those studying mechanics, as well as professionals involved in vector analysis and moment calculations.

kleeds
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Homework Statement


find the magnitude and angle of the moment

moment=-2.8i-1.53j+2.24k

force tension=2.4 kN

Homework Equations


rxf=rfsin(theta)

The Attempt at a Solution


i used the cross product to get i j and k
tried sin and cos of vectors but didnt work.
inverse tan of vectors won't give close to correct angles
 
Last edited:
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Welcome to PF!

As far I as I can tell, the first part of the question is simply asking what the magnitude of the given vector is. You have all three components of the vector.

What is the expression for the magnitude of a vector in terms of its components?
 
I have no idea. The last time i did vectors at least six months ago.
 
nevermind you square them all, add them, then take the square root.
 
kleeds said:
nevermind you square them all, add them, then take the square root.

Yeah.
 

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