Momentum and percent kinetic energy loss

AI Thread Summary
A 1200 kg car traveling at 20 m/s collides with a stationary 1400 kg car, locking together post-collision. The calculation for their speed after the collision, considering an 80% kinetic energy loss, initially led to confusion, but the correct approach involves using 1/5 of the initial kinetic energy for the final kinetic energy. The final speed of the vehicles is determined to be 6.1 m/s, aligning with textbook answers. Inelastic collisions do not require all kinetic energy to be lost, but a completely inelastic collision occurs when the objects stick together, conserving momentum while losing energy. Understanding the distinction between inelastic and completely inelastic collisions is crucial for solving related problems.
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Homework Statement


1.) A 1200 kg car traveling at 20 m/s collides with a stationary 1400 kg car. The two cars lock together. Determine the speed of the vehicles immediately after the collision if 80% of the initial kinetic energy is converted to heat and sound during the collision

2.) Must all kinetic energy be lost in a collision for the collision to be considered completely inelastic? Explain

Homework Equations


Ek = 1/2mv^2

The Attempt at a Solution


For both of these questions I have the answers to them in the book but I can't seem to arrive at/understand the solution.
1.) 80% loss so..
4/5 Ekintial = Ekfinal
(4/5) * (1/2)(1200 kg)(20 m/s)2 + 0 = (1/2)(1200 kg + 1400 kg)(v2)
v^2 = 147.6923 m/s
v = 12.15 m/s
The answer should be 6.1 m/s according to my textbook though.

2. ) "No. As much as possible must be lost without violating the Law of Conversation of momentum" is the answer in the book.

Does this mean the maximum energy lost while the momentum of the system is equal for both the initial and final?

also, how do I know if an equation is completely inelastic rather than just inelastic?
 
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physicsstudent30192 said:
1.) 80% loss so..
4/5 Ekintial = Ekfinal

check ,why using lost energy for calculation?
 
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physicsstudent30192 said:
how do I know if an equation is completely inelastic rather than just inelastic?

if the dissipative forces /inelastic deformations are there then one can say the collision is inelastic-the proof is non equality of energy before and energy after the event. however momentum is conserved.
completely inelastic means bodies joined/stick together during collision due to inelastic forces.
 
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drvrm said:
check ,why using lost energy for calculation?

Oh wow, I should read over the questions better...changed the 4/5 to 1/5 and it worked. Thanks drvrm for both answers.
 
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