Momentum Eigenstate: Meaning of <psi|p|psi>, etc.

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Homework Help Overview

The discussion revolves around the interpretation of expressions in quantum mechanics involving Dirac notation, specifically the terms , , and . Participants are exploring the mathematical context and implications of these expressions in relation to momentum and position operators.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to clarify the meaning of Dirac notation and its application to quantum mechanical operators. Questions arise regarding the interpretation of specific expressions and the derivation of related values, such as the mean momentum and position.

Discussion Status

Some participants are providing definitions and clarifications about the notation used, while others are expressing confusion about specific calculations and their implications. There is an ongoing exploration of how to apply the given wave function to derive meaningful results related to the operators.

Contextual Notes

Participants are working within the constraints of quantum mechanics and the specific mathematical framework of Dirac notation. There is a noted uncertainty regarding the derivation of certain values and the application of the operators involved.

imagemania
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Homework Statement


I am trying to translate what is meant by:
<psi | p | psi>
<psi|p^2|psi>
<psi | x | psi>
In a mathematicaly context as shown by this link:

http://answers.yahoo.com/question/index?qid=20110521103632AASz9Hm


Can anyone specify what these mean?

Thanks!
 
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hi imagemania! :smile:

<| denotes a row vector

|| denotes a matrix

|> denotes a column vector :wink:
 
Ok, but I am still not following how he got one for the first question:
<psi | p | psi> = 0

for the integral:
\psi = \int_{-\infty}^{\infty} {e}^{-\alpha {(k-{k}_{0})}^{2}}{e}^{ikx} dk

Thanks
 
not following you …

ψ is as given, and p is the momentum operator :confused:
 
Perhaps i'll ignore that post and go back to the fundamental question. From my understanding,
\bar{p}=\frac{hk}{2 \pi}. Knowing \psi is there a way to deduce a better answer to \bar{p} or is it just as I said here?

I am also unsure about the equation for mean value of x.

Thanks :)
 
It's Dirac notation. For an operator A, you can write
\langle \psi | \hat{A} | \psi \rangle = \int \psi^*(x)\hat{A}\psi(x)\,dx
You've been given the wave function. What you need to do next is look up how to express the operators x, p, and p2 appropriately.
 

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