Monte Carlo in high energy physics

JoePhysicsNut
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Why is it necessary to use Monte Carlo methods in high energy physics?

There is Feynman calculus to evaluate matrix elements for various interactions and the relativistic Fermi's Golden Rule for decays and scattering to obtain a decay width or differential cross section.

What are we missing that forces us to use Monte Carlo methods to obtain numerical results instead of having functional forms for distributions?
 
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Many (most) interactions are way too complicated to study them in an analytic way. In particular, hadron collisions can produce something like 10++ new hadrons - it is impossible to calculate that.

To make things worse, the detector responses are even more complicated - you need simulations.
 
Matrix elements are used to calculate cross sections in hep.

The Monte Carlo part, including the showering of particles and hadronization etc. are added onto calculations to try to model the rest of the interaction. In general, the part we can calculate perturbatively ( Feynman diagrams etc. ) , we do.

The parts we can't calculate have classical models based on previous experiments ( with theoretical motivations)
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
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