V
s would be a sensible place to start. Your calculation is correct. I'm not sure why you are having doubts.
You do seem to have assumed that I
S = I
D. If you are not confident about that assumption, ask yourself where the current I
D can go. It is, after all, a flow of electric charge, so what goes into the MOSFET must come out. And where can it go? Let's think about the gate current first. Remember that the O in MOSFET stands for oxide: the insulating layer of silicon dioxide. How much current flows through an insulating layer? So where does that leave for I
D to go?
Apparently we are supposed to answer questions this way, not just doing your homework for you. But I presume your next step will be to work out V
gs by plugging the numbers straight into the second equation, won't it?

And that should tell you the current through R
1.
And, using your conclusion about the gate current, you should be able to work out the current through R
2 without needing a calculator... and thus the value of R
1.
Alternatively, using your conclusion about the gate current, you could treat R1 and R2 as a potential divider - you may have derived a formula for this in your lessons. It's the same idea but just means you don't have to work out the currents explicitly. For instance if the required voltage at the junction of R
1 and R
2 were 4.5V (it's not) then R2 would have to be 9 times R
1.
Is that helpful or did you have a different difficulty?