Most Probable Radius of a 2s Hydrogenic Atom?

  • Thread starter Thread starter pcheminsanity
  • Start date Start date
  • Tags Tags
    Probability Radial
pcheminsanity
Messages
2
Reaction score
0

Homework Statement



Determine the most probable radius of an electron for a 2s hydrogenic atom.

Homework Equations



r*=a0/Z where a0 is Bohr radius

The Attempt at a Solution



Well, I know that the answer is ~5.2a0/Z. The book tells me that the most probable radius for hydrogen (EDIT - a 2s hydrogen shell I mean) is 5.2a0 - thus I know that the answer is simply 5.2a0/Z (275pm/Z) for the series of hydrogenic atoms. My only problem is this: I don't know how to get the coefficient of 5.2, and presumably simply getting it out of the book is not the right way to do it. I think it may have to do with taking the derivative of the wavefunction but I'm unsure...Any help would be appreciated, thanks!
 
Physics news on Phys.org
The probability for an electron to be found in the radial range r+dr can be determined using the wavefunction for the 2S state:

P(r+dr)=|\Psi_{200}|^24\pi r^2dr

Now if you want to find the most probable value, your looking for the value of r, such that P(r+dr) is a maximum. Think back to calculus. What is the condition for a function, P(r) to be maximum?

HINT: The condition involves \frac{dP}{dr}
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top