James walks 2 km away from home in 30 minutes. He then turns around and walks back home along the same path, also in 30 minutes. Calculate James’ average speed and average velocity. My answer: s = d / t = 4000m / 3600s = 1,11 m.s -1 v = Δx / Δt = 0 m / 3600 s = 0 m.s-1 I'm just confuse about one part in velocity, so if your displacement is 0 the velocity is always 0? yeah?