Motion problem for constant acceleration of rabbit

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Homework Help Overview

The problem involves a rabbit running at a constant speed while being chased by a wolf that accelerates from rest. The scenario includes calculating the time it takes for the wolf to catch the rabbit, considering the initial distance between them.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the timing of the wolf's chase relative to the rabbit's position, questioning how to account for the initial distance between them. Some participants present equations for the positions of both the rabbit and the wolf, while others suggest simplifying the problem by setting their positions equal to find the catch-up time.

Discussion Status

The discussion is ongoing, with participants providing insights into the setup of the equations and clarifying the initial conditions. There is a focus on understanding the implications of the initial distance and how it affects the calculations.

Contextual Notes

Participants note that the initial distance between the rabbit and wolf is 1.5 meters, which is a critical factor in the problem setup. There is an emphasis on ensuring that this distance is appropriately accounted for in the equations used to find the solution.

chroncile
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Homework Statement


A rabbit runs past a bush where a wolf is lying in wait. The rabbit is running at 3.0 m/s. The wolf leaps out 0.50 seconds after the rabbit has passed and accelerates at 1.2 m/s2 chasing after the rabbit. If the wolf can keep up this acceleration, how long will it take for the wolf to catch the rabbit?


Homework Equations


d = vi * t + 0.5 * a * t^2


The Attempt at a Solution


I got 5.85 s, but the answer is 5.46 s so I did it wrong.
 
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When did you measure the time from? Hint: Where is the rabbit when the wolf starts chasing?

Show how you got your answer.
 
tR = tw + 0.5 s
dw = dr + 1.5 m

Wolf:

vi = 0
a = 1.2 m/s2

d = vit + 0.5 at2
d = 0.5(1.2)t2
d = 0.6t2

Rabbit:

v = 3.0 m/s
d = v * t
d = 3.0t

Since tr = tw + 0.5 s
dr = 3.0(tw + 0.5)
dr = 3.0tw + 1.5

Wolf:

Since dw = dr + 1.5

0.6t2 = 3.0t + 1.5 + 1.5
0.6t2 - 3.0t - 3.0

t = 5.85 or -0.85
 
chroncile said:
tR = tw + 0.5 s
This is true.
dw = dr + 1.5 m
This is only true at the moment the wolf starts moving. Skip it.

Wolf:

vi = 0
a = 1.2 m/s2

d = vit + 0.5 at2
d = 0.5(1.2)t2
d = 0.6t2
Good. This is the wolf's position measured from his starting point.

Rabbit:

v = 3.0 m/s
d = v * t
d = 3.0t

Since tr = tw + 0.5 s
dr = 3.0(tw + 0.5)
dr = 3.0tw + 1.5
Good. This is the rabbit's position measured from the wolf's starting point.

Wolf:

Since dw = dr + 1.5
Nah. Just set the two positions equal to solve for when the wolf reaches the rabbit.
 
Okay, great I got the right answer, but can you please explain to me why it's not + 1.5?
 
chroncile said:
Okay, great I got the right answer, but can you please explain to me why it's not + 1.5?
Initially the distance between them is 1.5 m. But the wolf catches up to the rabbit, which means they are at the same place. You've already included that head start when you wrote your equations.

The way I would solve it (equivalent to yours of course), measuring everything from the moment and position of the wolf when he starts chasing:

Xr = 3t + 1.5

Xw = 0.6t^2

Just set them equal.
 

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