Motion problem for constant acceleration

AI Thread Summary
A pedestrian is attempting to catch a bus that accelerates from rest at 1.0 m/s² while the pedestrian runs at a constant speed of 6.0 m/s from a distance of 16 m. The discussion revolves around determining whether the pedestrian can catch the bus and how far he must run if he does. Participants suggest using the displacement equations for both the bus and the pedestrian to find a common time where their distances equal. The hint emphasizes the need to consider individual velocities and accelerations for both parties. Ultimately, the problem requires solving for time and distance to ascertain the outcome of the chase.
chroncile
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Homework Statement


A pedestrian is running at his maximum speed of 6.0 m/s trying to catch a bus that is stopped at a traffic light. When he is at 16 m from the bus, the light changes and the bus pulls away from the pedestrian with an acceleration of 1.0 m/s2.

Does the pedestrian catch the bus and, if so, how far does he have to run? (If not, what is the pedestrian's distance of the closest approach?)


Homework Equations


d = vi * t + 0.5 * a * t2


The Attempt at a Solution


I don't understand how to do it :frown:
 
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chroncile said:

Homework Equations


d = vi * t + 0.5 * a * t2

The Attempt at a Solution


I don't understand how to do it :frown:
Show us your best try. :biggrin: What is your equation for the displacement of the bus, from the traffic light, as a function of time t? What is your equation for the pedestrian's displacement from the traffic light as a function of time t? Is there ever a real-valued, positive time t where the displacements are equal? :wink:

Hint: there's a more general equation that you might consider using, instead of the one you quoted (and don't forget the bus and the pedestrian each have their own individual velocities and accelerations):

d = di + vit + ½at2
 
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