Calculating Electrostatic Work: q1, q2, k, W

AI Thread Summary
To calculate the work W done by the electrostatic force on a moving point charge q2, one must consider the change in electrostatic potential energy as the charge moves from point (x1, 0) to (x2, y2). The work can be expressed using Coulomb's law, incorporating the charges q1 and q2, along with Coulomb's constant k. Understanding the concept of potential energy for charged particles is crucial, as it parallels gravitational potential energy. Participants in the discussion emphasize the importance of showing initial problem-solving attempts for better guidance. Clarifying these concepts will aid in accurately calculating the work done in joules.
HELLO11
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Homework Statement



A point charge with charge q1 is held stationary at the origin. A second point charge with charge q2 moves from the point (x1, 0) to the point (x2,y2).

How much work W is done by the electrostatic force on the moving point charge?

Express answer in joules. Use k for Coulomb's constant


Homework Equations



http://i283.photobucket.com/albums/kk319/bigcurly_09/render.gif...
 
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Think about how you would define moving, say, a rock from one elevation to another. At each location, the rock has a certain "gravitational potential energy", and the amount of work you do is equal to the differences in the gravitational potential energies.

Now think about how you define potential energies for charged particles.
 
can any help me, i still don't get it
 
HELLO11 said:
can any help me, i still don't get it

What exactly don't you get?

A good first step would be posting your attempt at solving the problem.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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