Multiple-choice question, Electric field and potential

AI Thread Summary
The discussion revolves around the relationship between the charges on two positively charged metal spheres connected by a conducting wire. When the wire is connected, the potentials of both spheres equalize due to the conductive nature of the wire, leading to the equation q1/q2 = a/b, where a and b are the radii of spheres A and B, respectively. The potential for each sphere is given by V = q/(4∏εr), confirming that the charges are proportional to their radii. The discussion also raises questions about the behavior of charges if the wire is cut and reconnected after altering the charges on the spheres. Ultimately, the key takeaway is that the conducting wire maintains equal potential between the spheres, regardless of their individual charges.
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A positively-charged metal sphere A of reaius a is jointed by a long conducting wire to another positively charged metal sphere B of radius b. Assume that B is far away from A. If the charges on A and B are respectively q1 and q2, what is the ratio q1:q2?

Relevant equations
V=q/(4∏εr)

a) a^2:b^2
b) a:b
c) b^2:a^2
d) b:a

Solution:
The conducting wire ensures that the potentials of the two spheres are the same. Since they are far apart, the charge of any sphere will not influence the potential of one another.
V(sphere a)=V(sphere b)
q1/(4∏εa) = q2/(4∏εb)
∴ q1/q2=a/b
This is the solution from the book.
Why the potentials of the two sphere are the same when they joined by a conducting wire?
 
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Suppose you

- Cut the wire somewhere between the spheres,
- Put a charge on the spheres such that two spheres have different potentials, and
- Reattach the cut ends of the wire.

What flows down the wire?
 
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