Multiplying equations - spiral coil heat transfer

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SUMMARY

The discussion centers on the multiplication of equations 8 and 9 related to spiral coil heat transfer. The user seeks clarification on how to derive equation 10 from the multiplication of the left-hand sides (LHS) and right-hand sides (RHS) of equations 8 and 9. The conclusion indicates that the user ultimately did not need to multiply the equations but rather required extensive manipulation of the equations to reach their goal.

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"multiplying equations" - spiral coil heat transfer

Hi, I was wondering if anyone could explain to me what is meant in this article by "Multiplying equations 8 & 9". I have both equation 8 and equation 9 however I cannot seem to work out how to get equation 10...not sure if it's something simple I'm missing, thanks in advance.

9vees8.png
 
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That means \mbox{LHS of (8)} \times \mbox{LHS of (9)} = \mbox{RHS of (8)} \times \mbox{RHS of (9)}. (Although I don't quite understand how they get from there to (10).)
 


Ok cheers, I did try that but I couldn't get it. Will have to try again, thanks :)
 


Thanks for your help, didn't end up needing to multiply them just required a lot of tedious manipulation!
 

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