[Multivariable Calculus] Implicit Function Theorem

David Donald
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I am having trouble doing this problem from my textbook... and have
no idea how to doit.

1. Homework Statement

I am having trouble doing this problem from my textbook...

Show that the equation x + y - z + cos(xyz) = 0 can be solved for z = g(x,y) near the origin. Find dg/dx and dg/dy

(dg/dx and dg/dy are partial derivatives)

Homework Equations


Implicit function theorem.

The Attempt at a Solution


I tried computing dg/dx and dg/dy like it told me but
I think that isn't what its asking..
 
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David Donald said:
I am having trouble doing this problem from my textbook... and have
no idea how to doit.

1. Homework Statement

I am having trouble doing this problem from my textbook...

Show that the equation x + y - z + cos(xyz) = 0 can be solved for z = g(x,y) near the origin. Find dg/dx and dg/dy

(dg/dx and dg/dy are partial derivatives)

Homework Equations


Implicit function theorem.

The Attempt at a Solution


I tried computing dg/dx and dg/dy like it told me but
I think that isn't what its asking..
I think that the trick here is to recognize that if x and y are both close to 0, then xyz is also close to zero, so what can you say about cos(xyz)?
 
David Donald said:
I am having trouble doing this problem from my textbook... and have
no idea how to doit.

1. Homework Statement

I am having trouble doing this problem from my textbook...

Show that the equation x + y - z + cos(xyz) = 0 can be solved for z = g(x,y) near the origin. Find dg/dx and dg/dy

(dg/dx and dg/dy are partial derivatives)

Homework Equations


Implicit function theorem.

The Attempt at a Solution


I tried computing dg/dx and dg/dy like it told me but
I think that isn't what its asking..

You are given an equation of the form ##f(x,y,z)=0## and an initial point ##(0,0,z_0)## that satisfies it (where I will let you figure out the value of ##z_0##). The implicit function theorem states that for certain conditions on the derivatives of ##f## in a neighborhood of ##(0,0,z_0)##, the equation is solvable for ##z## in terms of ##(x,y)##, near ##(0,0)##. Does your given ##f## satisfies those conditions? Does the theorem apply to your function?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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