Multivariate Calculus Chain Rule.

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SUMMARY

The forum discussion focuses on applying the chain rule in multivariate calculus to analyze the relationship between voltage (V), current (I), and resistance (R) in an electrical circuit using Ohm's law (V = IR). The specific problem involves calculating the rate of change of current (dI/dt) given the values R = 400 ohms, I = 0.08 A, dV/dt = -0.01 V/s, and dR/dt = 0.03 ohms/s. The correct application of the multiplication rule leads to the solution of dI/dt = -3.1 * 10^(-5) A/s.

PREREQUISITES
  • Understanding of multivariate calculus, specifically the chain rule.
  • Familiarity with Ohm's law (V = IR).
  • Knowledge of differentiation and rates of change.
  • Basic electrical engineering concepts related to voltage, current, and resistance.
NEXT STEPS
  • Study the application of the chain rule in multivariable calculus.
  • Learn how to differentiate functions involving multiple variables.
  • Explore advanced topics in electrical circuits, including transient analysis.
  • Practice solving problems involving rates of change in physical systems.
USEFUL FOR

Students of calculus, electrical engineering students, and professionals involved in circuit analysis who need to understand the dynamics of voltage, current, and resistance over time.

jaguar7
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Homework Statement



Apply the two cases of th change rule. For example: The voltage V in an electrical circuit is slowly decreasing as a battery wears out and the resistance R is slowly increasing as the resistor heats up Use Ohm's law V=IR to find how the current is changing (with respect to time) at the instant that R = 400 ohms, I = 0.08A, dV/dt = -0.01V/s, and dR/dt = .03 ohms/s. (Answ: -3.1 * 10^(-5)A/s)

Homework Equations



I guess we have three variables, V, I, and R. Do we use the multiplication rule and get (dV/dt = R dI/dt + I dR/dt) ?

The Attempt at a Solution

 
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jaguar7 said:

Homework Statement



Apply the two cases of th change rule. For example: The voltage V in an electrical circuit is slowly decreasing as a battery wears out and the resistance R is slowly increasing as the resistor heats up Use Ohm's law V=IR to find how the current is changing (with respect to time) at the instant that R = 400 ohms, I = 0.08A, dV/dt = -0.01V/s, and dR/dt = .03 ohms/s. (Answ: -3.1 * 10^(-5)A/s)



Homework Equations



I guess we have three variables, V, I, and R. Do we use the multiplication rule and get (dV/dt = R dI/dt + I dR/dt) ?
Sure. Solve this equation for dI/dt, and evaluate it for the given values of I, R, dV/dt, and dR/dt.
 

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