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## Homework Statement

The mutual inductance between two coils is 0.0100 H. The current in the first coil changes uniformly from 2.7 A to 5.0 A in 0.160 s. If the second coil has a resistance of 0.600 Ω, what is the magnitude of the induced current in the second coil?

Please show steps

## Homework Equations

I=V/R

V=M(di/dt)

## The Attempt at a Solution

I tried everything but I still couldn't figure out the magnitude of the induced current in the second coil

What I did first is I solved for V_2 using M(di_1/dt)

di_1=(5-2.7)=2.3 A

dt =0.16 s

M=.01 H

and I got V_2 to be around .14

then once I got V_2 I divided it by .6 and got I to be around .23A but my friend keeps on getting the answer to be .344 A

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