My calculation of the density of the universe at (10^60)th of its present age

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SUMMARY

The discussion centers on calculating the density of the universe at a time approximately 10^60 times its current age, using specific formulas involving the Planck length, Planck density, and current cosmic density. The calculations yield a factor of 8.17722722*10^60 when dividing the distance light has traveled since the Big Bang by the Planck length. Further computations indicate that the universe's density would need to exceed the Planck density by nearly 60 orders of magnitude, raising questions about the assumptions underlying Planck density calculations. The conversation also touches on calculating electric permittivity and magnetic permeability at Planck time.

PREREQUISITES
  • Understanding of cosmological constants, specifically Hubble's constant (70 km/s/Mpc)
  • Familiarity with Planck units, including Planck length and Planck density
  • Knowledge of fundamental physics concepts such as electric permittivity and magnetic permeability
  • Basic proficiency in mathematical operations involving exponents and scientific notation
NEXT STEPS
  • Research the implications of Planck density in cosmology and its relation to massive particles
  • Study the derivation and significance of Hubble's constant in cosmic expansion
  • Explore the calculations of electric permittivity and magnetic permeability in quantum field theory
  • Investigate the concept of cosmic inflation and its effect on early universe density
USEFUL FOR

Astronomers, physicists, and cosmologists interested in the early universe, density calculations, and the fundamental properties of space-time at Planck scales.

kmarinas86
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If you divide the distance light traveled since the Big Bang by the Planck length, you get a factor of 8.17722722*10^60.

((1 / (70 ((km / s) / Mpc))) * (1 (light year / year))) / sqrt(((h / (2 * pi)) * G) / (c^3)) = 8.17722722 * 10^60

If you cube this value, you get the factor by which the volume was smaller.

(((1 / (70 ((km / s) / Mpc))) * (1 (light year / year))) / sqrt(((h / (2 * pi)) * G) / (c^3)))^3 = 5.4678702 * 10^182

Try dividing the Planck density by the current density of the universe.

(5.1 * ((10^96) (kg / (m^3)))) / (5 * ((10^(-30)) (g / (cm^3)))) = 1.02 × 10^123

Presumably, the density of the universe would have to be greater than the Planck density at Planck time, by almost 60 orders of magnitude. But scientists say otherwise. Knowing that the scientists are more likely to be right than I, can somebody explain why this result is different by almost 60 orders of magnitude? Does the Planck density ignore radiation and only consider massive particles?

As an aside question, how would you calculate the electric permittivity and magnetic permeability of the universe at Planck time?
 
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