N type material ,solid state physics

helpcometk
Messages
71
Reaction score
0

Homework Statement


Show that for N-type material the carrier concentration is roughly the donor
atom concentration. Explain why a N-type material is conducting at much lower
temperature then a intrinsic semiconductor


Homework Equations



maybe no equations are needed here

The Attempt at a Solution



The number of carriers in the conduction and valence band with no externally applied bias is called the equilibrium carrier concentration. For majority carriers, the equilibrium carrier concentration is equal to the intrinsic carrier concentration plus the number of free carriers added by doping the semiconductor. Under most conditions, the doping of the semiconductor is several orders of magnitude greater than the intrinsic carrier concentration, such that the number of majority carriers is approximately equal to the doping.
 
Physics news on Phys.org
For N-type material, the majority carriers are electrons and the material is doped with donor atoms that introduce additional free electrons into the conduction band. Since the doping is several orders of magnitude greater than the intrinsic carrier concentration, the equilibrium carrier concentration is roughly equal to the donor atom concentration. N-type semiconductors are able to conduct at much lower temperatures than intrinsic semiconductors because the number of free electrons is much greater. The additional free electrons mean that there are more electrons available to cross the band gap, allowing current to flow more easily.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top