Natural frequency of oscillating electron

AI Thread Summary
To find the natural frequency of an oscillating electron emitting light at a wavelength of 510 nm, the Q value of 3 x 10^7 is crucial for calculations. The relationship between Q, natural frequency (ω0), and damping coefficient (γ) is essential, but the specific value of γ for an electron is unclear. The width of the resonance can be calculated using the formula 2γω0, but determining γ remains a challenge. The discussion emphasizes the need for clarity on the damping coefficient for an electron in this context. Understanding these parameters is vital for solving the problem effectively.
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Homework Statement



a) Light of wavelength 510nm is emitted by an electron in an atom behaving as a lightly damped simple harmonic oscillator with a Q value of 3 x 107. Find the natural frequency of the system.

b) Find the width of the resonance.

Homework Equations



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The Attempt at a Solution



Knowing the Q value means that I need to know γ in order to get ω0. Gamma is b/m and m can be found in tables, but what is b for an oscillating electron?
 
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For part b, I know that the width of the resonance is 2γω0, but again, what is gamma for an oscillating electron?
 
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