Need help finding what formula to use?

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To determine the maximum height a tennis ball reaches when hit at an initial velocity of 26 m/s at a 54-degree angle, the relevant formula is v^2 = v_o^2 + 2aΔy. At the peak of its trajectory, the vertical velocity is zero, so this value is used in the equation. The initial vertical velocity calculated is 21.0 m/s, and the acceleration due to gravity is -9.8 m/s^2. By substituting these values into the formula, the correct height of 22.6 meters can be derived. The discussion emphasizes the importance of using the correct initial vertical velocity for accurate calculations.
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Homework Statement


A tennis player hits a ball at ground level, giving it an initial velocity of 26 m/s^2 at 54 degrees above the horizontal. How high above the ground does the ball go?


Homework Equations


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The Attempt at a Solution


I found out the horizontal velocity, which is 15.3 and the vertical velocity which is 21.0
 
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In projectile motion the highest point occurs right in the middle when the vertical speed is zero.
 
Yeah, I understand that. What formula would I use to actually find the height though?
 
v^2=v_o^2+2a\Delta y
 
So if at the highest point there is a vertical speed of zero, would I put zero in for v^2? 26 for initial velocity and -9.8 for acceleration?
 
Yes.
 
the answer is 22.6, but when i do that I get 34.49
 
ohh... I think I needed to put in the vertical velocity which was 21.0 instead. Then that formula works.
 
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