How Do You Graph Velocity for Different Speeds and Time Intervals?

[kevinf]

need urgent help on graphing velocity graphs

Homework Statement

(a) You walk 71.4 m at a speed of 1.22 m/s and then run 71.4 m at a speed of 3.05 m/s along a straight track.

(b) You walk for 1.16 min at a speed of 1.22 m/s and then run for 1.16 min at 3.05 m/s along a straight track.

(c) Graph x versus t for both cases and indicate how the average velocity is found on the graph. (Do this on paper. Your instructor may ask you to turn in this graph.)

Homework Equations

The Attempt at a Solution

i need help on graphing this for part c. i already graphed 1.16(60) divide by 1.22 on the graph but i don't know how to do the second speed. any help would be apprecieated

 

[learningphysics]

Can you describe where you're getting stuck? You found the time for the first distance... just add the time for the second distance...

 

[m2003]

Hello,

Graphing velocity graphs can seem daunting, but it's actually a straightforward process. The first step is to plot the data points on a graph with the time on the x-axis and the velocity on the y-axis. For part (a), you would plot two points - (0, 1.22) and (1.16, 3.05).

Next, you can connect these two points with a straight line to create the velocity graph. The slope of this line represents the average velocity, which can be found by calculating the rise over run, or (change in velocity)/(change in time). In this case, the change in velocity is 1.83 m/s (3.05-1.22) and the change in time is 1.16 min (1.16 min - 0 min). So the average velocity would be (1.83 m/s)/(1.16 min) = 1.58 m/s.

For part (b), you would plot two points - (0, 1.22) and (1.16, 3.05) - just like in part (a). However, since the time intervals are different, the slope of the line connecting these points would be different. You can follow the same process as in part (a) to find the average velocity for part (b).

I hope this helps! If you need further assistance, don't hesitate to reach out to your instructor or a tutor for additional support. Good luck with your graphs!