Need help please with pushing a block question

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The discussion revolves around calculating the coefficient of friction (μ) and the acceleration of a block under a force applied at an angle. The user has identified the forces acting on the block but is confused due to having two unknowns in their equations. The correct approach involves recognizing that the block will start moving when the frictional force equals the horizontal component of the applied force. Once the normal force (N) and frictional force (fr) are established, μ can be calculated using the formula μ = fr/N. Additionally, when pulling the block with the same force, the normal force decreases, affecting the acceleration.
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so I completely drew my work, as you can I need to find out the coeffiect of mu and the acceleration of the block. I did the Y and X forces and am stuck, because I have 2 unknowns with the X formula even if I sub in the Y into it. Am I doing somthing wrong or missing somthing here? Thanks for your help :)
 
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Your approach is correct. Post the exact text of the problem.
 
The site is down for my homework assignment, but that is indeed all they gave me, they only told me the force that is pushed against the block, the angle, and the weight of the block(1000N) and I am to find mu and acceleration of the block, They then say what is the acceleration of the block if you pull it with the same force and angle, using the same mu from the push. Ill post the question as soon as the site is back up
 
Now it is clear. Block will just start moving when frictional force fr is equal to F*cos20.
Now μ = fr/N. You know N and fr. Find μ.
When you pull the block with the same force, you can see that the normal force decreases.
 
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