Lewis
Need help with electric field calculation? Check out part B!
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I can't open your attachment. Why don't you cut and paste and put it in without the attachment?Lewis said:I'm having trouble with the question included in the attachment, part B specifically. If anyone could start me off it would be a great help!
Also, my answer for part A is included if anyone would care to check it
-Note: Chances are it's wrong
Lewis
I can't copy and paste cause it's a picture, however perhaps the following will work for you:
http://www.geocities.com/shinra_clan1/Physics1.JPG
Thanks a bunch!
http://www.geocities.com/shinra_clan1/Physics1.JPG
Thanks a bunch!
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I also get your answer to (A), with \lambda=Q/h.
I think the easiest way to do (B) is:
1. Use the field of a ring to get the field a distance z from a disk of charge Q. Use dq=2pi r dr/(pi r^2 Q) and integrate r from 0 to R.
This should give E=(2Q/R^2)[1-z/sqrt{z^2+R^2}].
2. Integrate E for the disk the same way you must have done for E for the ring for the hollow cylinder.
Let me know if you want to know the answer.
I think the easiest way to do (B) is:
1. Use the field of a ring to get the field a distance z from a disk of charge Q. Use dq=2pi r dr/(pi r^2 Q) and integrate r from 0 to R.
This should give E=(2Q/R^2)[1-z/sqrt{z^2+R^2}].
2. Integrate E for the disk the same way you must have done for E for the ring for the hollow cylinder.
Let me know if you want to know the answer.
Lewis
Cool, I got it now.
Thanks man, and sorry for the slow reply.
Thanks man, and sorry for the slow reply.