Shahryar
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berkeman said:Where is the problem from? Is it for schoolwork?
Shahryar said:No its in my engineering design problem.
HallsofIvy said:It would strike me as an obvious first step to use the facts that sin(20- \theta)= sin(20)cos(\theta)- cos(20)sin(\theta) and cos(20- \theta)= cos(20)cos(\theta)+ sin(20)sin(\theta).
That "20" looks strange for radian measure. If it is in degrees you should remember that \int sin(x)dx= -cos(x)+ C and \int cos(x)= sin(x)+ C only for x measured in radians.