Efficiency of a 265W Motor at 4.30A from 120V Line | Energy Usage in 1.50 Hours

  • Thread starter Thread starter aMo0oDi
  • Start date Start date
  • Tags Tags
    Urgent
AI Thread Summary
The discussion focuses on calculating the efficiency of a 265W motor that draws 4.30A from a 120V line and determining its energy usage over 1.50 hours. To find efficiency, the relationship between power, current, and voltage is emphasized, with relevant equations provided. The energy consumed by the motor can be calculated using the formula for power and the time duration. The importance of understanding power equations is highlighted for accurate calculations. Ultimately, the efficiency can be derived by plugging in the given values into the appropriate formulas.
aMo0oDi
Messages
10
Reaction score
0
What is the efficiency of a 265W motor that draws 4.30A from 120V line?
How much energy in Joules does this motor use in 1.50 hour?

thanks in advance..
 
Physics news on Phys.org
What have you tried? Do you know what power is?
 
power has two equations :
1) P(t)= W/t = -PE/t = q.V/t = I.V
2) P= I (I.R)
 
aMo0oDi said:
power has two equations :
1) P(t)= W/t = -PE/t = q.V/t = I.V
2) P= I (I.R)

Power can also be expressed as P=V^2/R

Now what is efficiency defined as?

Finally, what information are you given and what can you do with it?
 
aMo0oDi said:
power has two equations :
1) P(t)= W/t = -PE/t = q.V/t = I.V
2) P= I (I.R)
If W/t=IV
W=J/s
I=Amps
V=Volts

You just plug it in, then find the efficiency.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top