Need to find center of mass of a rod

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Homework Help Overview

The problem involves finding the center of mass of a uniform, L-shaped iron rod with specified dimensions. The setup includes coordinates for the corners of the rod and requires consideration of mass distribution along its length.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss breaking the rod into two parts to find the center of mass of each side separately. There are questions about how to proceed without given mass values, and some suggest that mass is proportional to length.

Discussion Status

The discussion is ongoing with various interpretations being explored. Some participants have offered guidance on how to approach the problem, while others are questioning the assumptions regarding mass and reference points.

Contextual Notes

Participants note the absence of mass values and discuss the implications of this for calculating the center of mass. There is also mention of the need for a diagram to clarify the positions of the centers of each side.

Oomair
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[SOLVED] Need to find center of mass of a rod

Homework Statement


Where is the center of mass of a uniform, L-shaped iron rod of sides X = 0.8 m and Y = 0.5 m, respectively? Take the corner to be at (x,y) = (0,0), with the X and Y sides along those axes, respectively. (Assume that the rod is so narrow that the dimensions of the outer bend are the same as those of the inner bend of the L.)



Homework Equations





The Attempt at a Solution



i don't know if this involves integration, but it doesn't look like it, i think that xcm = 1/length total * ( (.8)(0) +(.8)(.8), but it does not work out
 
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Start by finding the center of mass of each side separately. Then use that to find the center of mass of the complete object.
 
how do i know the center of mass if I am not given the mass?

i broke it into 2 parts

(ycm)(Mt) = (m1)(Y1) +(m2)(Y2) Y1 = 0 Y2 = .5, but the unknowns are mass

(xcm)(Mt) = (m1)(X1) + (m2)(X2) X1 = 0 X2 = .8
 
Oomair said:
how do i know the center of mass if I am not given the mass?
The mass of each side is proportional to its length. That's all you need.

i broke it into 2 parts

(ycm)(Mt) = (m1)(Y1) +(m2)(Y2) Y1 = 0 Y2 = .5, but the unknowns are mass

(xcm)(Mt) = (m1)(X1) + (m2)(X2) X1 = 0 X2 = .8
Careful here: X1, Y1 should be the center of one side; X2, Y2, the center of the other.
 
but should'nt X1 and Y1 be treated as the reference line?
 
Oomair said:
but should'nt X1 and Y1 be treated as the reference line?
Not sure what you mean. X & Y are the coordinates of the centers of each side. (Try drawing yourself a diagram.)
 
Last edited:
Break it and sum. Everything is linear when talking about center of mass
 
Check this to understand the center of mass better:
http://www.tubepolis.com/play.php?q=center%20of%20mass&title=Center%2Bof%2BMass%2C%2BConservation%2Bof%2BLinear%2BMomentum%2BPart%2B1&engine=1&id=ROYYNJkhG4g&img=http%253A%252F%252Fi.ytimg.com%252Fvi%252FROYYNJkhG4g%252Fdefault.jpg
 
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