Need to find the charge of this capacitor?

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    Capacitor Charge
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SUMMARY

The charge on capacitor C2 is calculated using the formula Q = C * V, where C is the capacitance and V is the voltage across the capacitor. Initially, the voltage across C2 was incorrectly set up in the loop equation. The correct equation is V2 + V3 - Vof C2 = 0, leading to the correct voltage of 2 V across C2. Thus, with a capacitance of 5.0 µF, the charge Q2 is confirmed to be 5 µC.

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Homework Statement


Given,

MTDnC.png


What is the charge on C2 (the highlighted capacitor).
The answer is supposed to be Q2 = 5 uC


Homework Equations


C=Q/V
Loop Rule?


The Attempt at a Solution


What I did, is using the loop rule on the smaller loop, I set up
V2 - V3 - Vof C2 = 0
6 V - 4 V = Vof C2
2 V = Vof C2

So since,
Vof C2 = Q2/C2

Then,
Q2 = (2 V)(5.0 uF)

And Q = 1.0x10-5 C, however that isn't the answer... It's supposed to be 5 uC.

Solution
Wow, I just figured it out, stupid mistake. It should be V2 + V3 - Vof C2 = 0. That fixes it.
 
Last edited:
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Well done - sometimes telling it so someone else focusses your mind and you see what went wrong.
 

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