# Need to find the second derivative of:

1. Aug 4, 2010

### 619snake

f(x)= 1/125(e5x)(5x-2)

I think this is the first derivative but I ain't good at math and gives me some headaches I used the product rule.. but still I have doubts =(

f '(x)= 1/125(5)(e5x)(5x-2) + (5)(1/125(e5x)

I need to understand how to do this

Last edited: Aug 4, 2010
2. Aug 4, 2010

Assuming you have $$f(x) = \frac{1}{125}e^{5x}(5x - 2),$$ you need to apply the product rule.

Given $$f(x) = g(x)h(x),$$

$$f'(x) = g'(x)h(x) + g(x)h'(x).$$

And you'll need the product rule again to find f''(x). Also, I'd leave the constant 1/125 out in front while taking the derivatives until the end.

3. Aug 4, 2010

### 619snake

Thanks Raskolnikov! Now I only need to identify which rule I need to use in each case.

4. Aug 4, 2010

Yep, you got it right (though I think you're overloading on parentheses :P)! For the second derivative, you have to use the product rule again on the first term since it has both a factor of e^5x and a factor of (5x - 2). However, you don't need the product rule for the 2nd term since it's just e^5x.

Try to find f''(x). Just post whatever answer you get or where you're getting stuck, and I'll help you from there if you need.

5. Aug 4, 2010

### 619snake

I'm not sure about this... as I said.. I haven't mastered this rules and is getting really messed up

f"(x)= ($$\frac{1}{125}$$)(25)e$$^{5x}$$(5x-2) + 5($$\frac{1}{125}$$(5)e$$^{5x}$$) + ($$\frac{1}{125}$$(5)e$$^{5x}$$)....

I dont know... think I got confused

6. Aug 4, 2010

$$f''(x) = \frac{1}{5}e^{5x}(5x - 2) + \frac{2}{5}e^{5x}.$$