Need to find torque so I can find the period

  • Thread starter Thread starter auk411
  • Start date Start date
  • Tags Tags
    Period Torque
AI Thread Summary
To determine the period of small oscillations for a rotating rod connected to a spring, the torque must be expressed as a function of the angle θ. The moment of inertia (I) of the rod can be calculated, but the spring constant (C) needs to be derived from the spring's force and the change in length as the rod rotates. The spring force is essential for calculating torque, which is linked to the angular displacement. Understanding the relationship between the spring's extension and the angle of rotation is crucial for solving the problem. This approach will lead to the correct calculation of the period of oscillation.
auk411
Messages
54
Reaction score
0

Homework Statement



A long uniform rod of mass .6 kg is free to rotate in horizontal plane about a vertical axis through its center. A spring with force constant k = 1850 N/m is connected horizontally between one end of the rod and a fixed wall. When the rod is in equilibrium, it is parallel to wall. What is the period of the small oscillations that result when the rod is rotated slightly an released?

Homework Equations



Torque = - C (a constant) \theta

T (period) = 2\pi\sqrt{I/C}.

The Attempt at a Solution



So, I can find I (the moment of inertia), but what I can't find is what the constant is supposed to be. I've been told to find the torque as a function of \theta. I just don't know how.

Also, I do realize that it's important that we are working with small angles.

It probably doesn't help that I can't really picture what is going on either.
 

Attachments

  • rod.jpg
    rod.jpg
    4.9 KB · Views: 1,037
Last edited:
Physics news on Phys.org
You need the spring force to get the torque. It depends on the change of length of the spring. Calculate the length change of the spring if the rod rotates by a small angle θ.


ehild
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top