Net Displacement (Probably very easy, but I don't get it)

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SUMMARY

The net displacement of a person who walks 0.6 km east, then 500 meters south, and climbs 180 meters vertically is calculated using the Pythagorean theorem. The horizontal displacement is determined by combining the eastward and southward movements, resulting in a base of approximately 780 meters. The total displacement is then calculated by incorporating the vertical height of 180 meters, leading to a final displacement of approximately 1100 meters. The angles of elevation and horizontal displacement must also be considered for a complete understanding of the problem.

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Homework Statement



A person walks on level ground 0.6 km east, then 500 meters south, and then climbs to the top of a building (height 180 meters). What is the net displacement of the person?

Homework Equations





The Attempt at a Solution



Really have no idea. I know that 600m east and then 500 m south equals a displacement of 1100 m. Or do you have to use Pythagorean theorem? And then for the extra 180 vertical meters, I have no idea.

Some help please.
 
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Really have no idea. I know that 600m east and then 500 m south equals a displacement of 1100 m.
No, it does not. Yes, you must use the Pythagorean theorem. That will give you the distance in the horizontal plane. Then you consider the 180 m up, which gives you a triangle in a vertical plane which has a height of 180 and a base of about 780. Use the Pythagorean theorem to find the distance from beginning to end.

The word "displacement" usually means the straight line distance AND the angles involved. You may have to find the angle in the horizontal triangle and the angle of elevation in the vertical triangle to complete the problem.
 
i never really understood triangles in a vertical plane thoughhh
 
Hey FAJ, use d=sqrt'sq 600 + sq 500 + sq 180'
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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