Net Electric Force on Charged Spheres

In summary, the three spheres with negative charges of 4.0 X 10^6 C, fixed at the vertices of an equilateral triangle with sides of 0.20 m, experience a net force of magnitude 6.2 N, directed at an angle of 150 degrees with respect to each side of the triangle. This can be determined through symmetry, without any calculations, as the net force must act in the middle between the two other charges, making an angle of 30 degrees below the horizontal axis.
  • #1
rum2563
89
1

Homework Statement


Three spheres, each with a negative charge of 4.0 X 10^6 C, are fixed at the vertices of an equilateral triangle whose sides are 0.20 m long. Calculate the magnitude and direction of the net force on each sphere.


Homework Equations


Fe = kq1q2 / r^2


The Attempt at a Solution



I used vector components to try to solve this question.

I think that we only have to find the net force on one of the spheres since the radius and the charges are same throughout the system. Sphere 1 is the "main" sphere from which I want to find out the net force.

Force of Sphere 2 on 1:
F2 = kq1q2 / r^2
= (9 X 10^9)(4.0 X 10^-6)^2 / (0.2)^2
= 3.6 N

For the x-component of force of sphere 2 on 1:

F2x = 3.6 X sin 30°
= 1.8 N

For the y-component of force of sphere 2 on 1:

F2y = 3.6 X cos30°
= 3.12 N


The force that was exerted by sphere 3 on 1 is the same force as 3.6 N since all the values are the same. Only the direction is different.

Here is the vector sum:

x = -3.6 - 1.8 = -5.4
y = 3.12

c^2 = 3.12 ^2 + (-5.4)^2
= 6.2365
= 6.2 N

Therefore, the net force is 6.2 N.

BUT... how do I get the angle Θ, because in the book it says 150° away from each side.


Please anyone help. It's just a little problem. Thanks.
 
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  • #2
rum2563 said:
BUT... how do I get the angle Θ, because in the book it says 150° away from each side.
The symmetry of the triangular arrangement should allow you to find the direction of the net force immediately--no calculation required.
 
  • #3
I have attached the picture of the system. Can you please elaborate a bit more please?

I am thinking that I have to subtract 30 from 180 to get 150. But I just don't know how to prove that in explainable terms.

Please help. Thanks.
 

Attachments

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  • #4
Look at your diagram. Along what line must the net force on charge 1 act? (Draw it.) What angle does that net force vector make with a side?
 
  • #5
lol. I am seriously confused. I am not sure how to draw but by using tan, I get 30 degress.

tan-1 = 3.12 / 5.4
= 30 degrees.

And I think that since the sphere 3 to sphere 1 line is horizontal, the angle which the net force makes with the horizontal line is 30 degrees. Therefore, 180 - 30 which is 150 degrees is the answer.

Am I on the right track? I know you said no calculations involved but this is the only way I am trying to figure this out.
 
  • #6
You can also just find the angle from the force components that you've already calculated, assuming you've done that correctly. Use a little trig.
 
  • #7
Ok, well then I think I almost got it right.
Thanks for your help. This is the first time I am studying electric force and I think that's pretty complicated.

Thanks anyways. All the best.
 
  • #8
rum2563 said:
lol. I am seriously confused. I am not sure how to draw but by using tan, I get 30 degress.
That's perfectly fine (I was just suggesting you do that while you were posting this.)

tan-1 = 3.12 / 5.4
= 30 degrees.

And I think that since the sphere 3 to sphere 1 line is horizontal, the angle which the net force makes with the horizontal line is 30 degrees. Therefore, 180 - 30 which is 150 degrees is the answer.

Am I on the right track? I know you said no calculations involved but this is the only way I am trying to figure this out.
All good. But realize that another solution to your trig equation for tan(theta) is theta = 210 degrees: that's equivalent to 30 degrees below the -x-axis or 150 with respect to the side of the triangle.

But try this. By symmetry, you know that the net force must act right smack in the middle between the two other charges. Since you know the angle between the sides is 60 degrees, the net force must make an angle of 30 degrees below the horizontal axis. Which gives you your answer of 150 degrees with respect to the sides with (almost) no calculation.
 
  • #9
Wow, thanks for your response. It actually made perfect sense to me. I am happy that you told me how it doesn't involve any calculation since 60 degrees must be divided by 2 since the net force vector goes exactly through the middle. Thanks very much.
 

What is the net electric force on a charged sphere?

The net electric force on a charged sphere is the sum of all the electrostatic forces acting on the sphere due to other charged particles in its vicinity. This force is a vector quantity, meaning it has both magnitude and direction.

How is the net electric force on a charged sphere calculated?

The net electric force on a charged sphere can be calculated using Coulomb's Law, which states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. This can be represented by the formula F = k * (q1 * q2)/r^2, where k is the Coulomb's constant, q1 and q2 are the charges of the two particles, and r is the distance between them.

Does the size of the charged sphere affect the net electric force?

Yes, the size of the charged sphere can affect the net electric force. As the size of the sphere increases, the distance between the charged particles also increases, resulting in a decrease in the electric force. However, for a uniformly charged sphere, the net electric force on a test charge located outside the sphere will be the same, regardless of the size of the sphere.

What is the impact of the charge distribution on the net electric force on a charged sphere?

The charge distribution on a charged sphere can affect the net electric force in different ways. For a uniformly charged sphere, the net electric force on a test charge located outside the sphere will be the same, regardless of the distribution of charge on the sphere. However, for a non-uniformly charged sphere, the net electric force may vary at different points on the surface of the sphere.

Can the net electric force on a charged sphere be zero?

Yes, the net electric force on a charged sphere can be zero if the sphere is in equilibrium, meaning the forces acting on it are balanced. This can happen when the sphere is placed in an electric field, and the forces due to the field and the charges on the sphere cancel each other out.

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